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0=4x^2-48x+990
We move all terms to the left:
0-(4x^2-48x+990)=0
We add all the numbers together, and all the variables
-(4x^2-48x+990)=0
We get rid of parentheses
-4x^2+48x-990=0
a = -4; b = 48; c = -990;
Δ = b2-4ac
Δ = 482-4·(-4)·(-990)
Δ = -13536
Delta is less than zero, so there is no solution for the equation
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